downpunxx@fedia.ioBanned from community to Lemmy Shitpost@lemmy.world · 2 years agomath checks outfedia.ioimagemessage-square106linkfedilinkarrow-up11.61Karrow-down112
arrow-up11.59Karrow-down1imagemath checks outfedia.iodownpunxx@fedia.ioBanned from community to Lemmy Shitpost@lemmy.world · 2 years agomessage-square106linkfedilink
minus-squareegeres@lemmy.worldlinkfedilinkarrow-up15arrow-down1·edit-22 years agoEehrm, acktually, the tweet is wrong 🤓 You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
minus-squarelseif@sopuli.xyzlinkfedilinkarrow-up3·2 years agoif it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
minus-squareSeasoned_Greetings@lemm.eelinkfedilinkarrow-up3·2 years agoI like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
minus-squareb000rg@midwest.sociallinkfedilinkEnglisharrow-up3·2 years agoThis honestly sounds like it could be the basis for a novella
minus-squareMigmog@lemm.eelinkfedilinkarrow-up2·2 years agoIt sounds like something that happens regularly during an update to software with a lot of users.
Eehrm, acktually, the tweet is wrong 🤓
You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
if it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
I like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
This honestly sounds like it could be the basis for a novella
It sounds like something that happens regularly during an update to software with a lot of users.
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